28x-49x^2-4=0

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Solution for 28x-49x^2-4=0 equation:



28x-49x^2-4=0
a = -49; b = 28; c = -4;
Δ = b2-4ac
Δ = 282-4·(-49)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-28}{-98}=2/7$

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